(3r+1)^2+(r+2)2=65

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Solution for (3r+1)^2+(r+2)2=65 equation: 



(3r+1)^2+(r+2)2=65

We move all terms to the left:

(3r+1)^2+(r+2)2-(65)=0

We multiply parentheses

(3r+1)^2+2r+4-65=0

We add all the numbers together, and all the variables

2r+(3r+1)^2-61=0

We move all terms containing r to the left, all other terms to the right

2r+(3r+1)^2=61

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